9x^2+8=575

Solution for 9x^2+8=575 equation:

9x^2+8=575

We move all terms to the left:

9x^2+8-(575)=0

We add all the numbers together, and all the variables

9x^2-567=0

a = 9; b = 0; c = -567;
Δ = b2-4ac
Δ = 02-4·9·(-567)
Δ = 20412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20412}=\sqrt{2916*7}=\sqrt{2916}*\sqrt{7}=54\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-54\sqrt{7}}{2*9}=\frac{0-54\sqrt{7}}{18}
=-\frac{54\sqrt{7}}{18}
=-3\sqrt{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+54\sqrt{7}}{2*9}=\frac{0+54\sqrt{7}}{18}
=\frac{54\sqrt{7}}{18}
=3\sqrt{7}
$